18b^2=2/18

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Solution for 18b^2=2/18 equation:



18b^2=2/18
We move all terms to the left:
18b^2-(2/18)=0
We add all the numbers together, and all the variables
18b^2-(+2/18)=0
We get rid of parentheses
18b^2-2/18=0
We multiply all the terms by the denominator
18b^2*18-2=0
Wy multiply elements
324b^2-2=0
a = 324; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·324·(-2)
Δ = 2592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2592}=\sqrt{1296*2}=\sqrt{1296}*\sqrt{2}=36\sqrt{2}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36\sqrt{2}}{2*324}=\frac{0-36\sqrt{2}}{648} =-\frac{36\sqrt{2}}{648} =-\frac{\sqrt{2}}{18} $
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36\sqrt{2}}{2*324}=\frac{0+36\sqrt{2}}{648} =\frac{36\sqrt{2}}{648} =\frac{\sqrt{2}}{18} $

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